Optimal. Leaf size=611 \[ \frac {55 b^{4/3} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} (17 A b-14 a B) F\left (\sin ^{-1}\left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right )|-7-4 \sqrt {3}\right )}{168 \sqrt {2} \sqrt [4]{3} a^{11/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {55 \sqrt {2-\sqrt {3}} b^{4/3} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} (17 A b-14 a B) E\left (\sin ^{-1}\left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right )|-7-4 \sqrt {3}\right )}{224\ 3^{3/4} a^{11/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}+\frac {55 b^{4/3} \sqrt {a+b x^3} (17 A b-14 a B)}{336 a^4 \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}-\frac {55 b \sqrt {a+b x^3} (17 A b-14 a B)}{336 a^4 x}+\frac {11 \sqrt {a+b x^3} (17 A b-14 a B)}{168 a^3 x^4}-\frac {17 A b-14 a B}{21 a^2 x^4 \sqrt {a+b x^3}}-\frac {A}{7 a x^7 \sqrt {a+b x^3}} \]
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Rubi [A] time = 0.36, antiderivative size = 611, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {453, 290, 325, 303, 218, 1877} \[ \frac {55 b^{4/3} \sqrt {a+b x^3} (17 A b-14 a B)}{336 a^4 \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}+\frac {55 b^{4/3} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} (17 A b-14 a B) F\left (\sin ^{-1}\left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right )|-7-4 \sqrt {3}\right )}{168 \sqrt {2} \sqrt [4]{3} a^{11/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {55 \sqrt {2-\sqrt {3}} b^{4/3} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} (17 A b-14 a B) E\left (\sin ^{-1}\left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right )|-7-4 \sqrt {3}\right )}{224\ 3^{3/4} a^{11/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {55 b \sqrt {a+b x^3} (17 A b-14 a B)}{336 a^4 x}+\frac {11 \sqrt {a+b x^3} (17 A b-14 a B)}{168 a^3 x^4}-\frac {17 A b-14 a B}{21 a^2 x^4 \sqrt {a+b x^3}}-\frac {A}{7 a x^7 \sqrt {a+b x^3}} \]
Antiderivative was successfully verified.
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Rule 218
Rule 290
Rule 303
Rule 325
Rule 453
Rule 1877
Rubi steps
\begin {align*} \int \frac {A+B x^3}{x^8 \left (a+b x^3\right )^{3/2}} \, dx &=-\frac {A}{7 a x^7 \sqrt {a+b x^3}}-\frac {\left (\frac {17 A b}{2}-7 a B\right ) \int \frac {1}{x^5 \left (a+b x^3\right )^{3/2}} \, dx}{7 a}\\ &=-\frac {A}{7 a x^7 \sqrt {a+b x^3}}-\frac {17 A b-14 a B}{21 a^2 x^4 \sqrt {a+b x^3}}-\frac {(11 (17 A b-14 a B)) \int \frac {1}{x^5 \sqrt {a+b x^3}} \, dx}{42 a^2}\\ &=-\frac {A}{7 a x^7 \sqrt {a+b x^3}}-\frac {17 A b-14 a B}{21 a^2 x^4 \sqrt {a+b x^3}}+\frac {11 (17 A b-14 a B) \sqrt {a+b x^3}}{168 a^3 x^4}+\frac {(55 b (17 A b-14 a B)) \int \frac {1}{x^2 \sqrt {a+b x^3}} \, dx}{336 a^3}\\ &=-\frac {A}{7 a x^7 \sqrt {a+b x^3}}-\frac {17 A b-14 a B}{21 a^2 x^4 \sqrt {a+b x^3}}+\frac {11 (17 A b-14 a B) \sqrt {a+b x^3}}{168 a^3 x^4}-\frac {55 b (17 A b-14 a B) \sqrt {a+b x^3}}{336 a^4 x}+\frac {\left (55 b^2 (17 A b-14 a B)\right ) \int \frac {x}{\sqrt {a+b x^3}} \, dx}{672 a^4}\\ &=-\frac {A}{7 a x^7 \sqrt {a+b x^3}}-\frac {17 A b-14 a B}{21 a^2 x^4 \sqrt {a+b x^3}}+\frac {11 (17 A b-14 a B) \sqrt {a+b x^3}}{168 a^3 x^4}-\frac {55 b (17 A b-14 a B) \sqrt {a+b x^3}}{336 a^4 x}+\frac {\left (55 b^{5/3} (17 A b-14 a B)\right ) \int \frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\sqrt {a+b x^3}} \, dx}{672 a^4}+\frac {\left (55 \sqrt {\frac {1}{2} \left (2-\sqrt {3}\right )} b^{5/3} (17 A b-14 a B)\right ) \int \frac {1}{\sqrt {a+b x^3}} \, dx}{336 a^{11/3}}\\ &=-\frac {A}{7 a x^7 \sqrt {a+b x^3}}-\frac {17 A b-14 a B}{21 a^2 x^4 \sqrt {a+b x^3}}+\frac {11 (17 A b-14 a B) \sqrt {a+b x^3}}{168 a^3 x^4}-\frac {55 b (17 A b-14 a B) \sqrt {a+b x^3}}{336 a^4 x}+\frac {55 b^{4/3} (17 A b-14 a B) \sqrt {a+b x^3}}{336 a^4 \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}-\frac {55 \sqrt {2-\sqrt {3}} b^{4/3} (17 A b-14 a B) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} E\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{224\ 3^{3/4} a^{11/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}+\frac {55 b^{4/3} (17 A b-14 a B) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} F\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{168 \sqrt {2} \sqrt [4]{3} a^{11/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}\\ \end {align*}
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Mathematica [C] time = 0.04, size = 72, normalized size = 0.12 \[ \frac {x^3 \sqrt {\frac {b x^3}{a}+1} (17 A b-14 a B) \, _2F_1\left (-\frac {4}{3},\frac {3}{2};-\frac {1}{3};-\frac {b x^3}{a}\right )-8 a A}{56 a^2 x^7 \sqrt {a+b x^3}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.82, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (B x^{3} + A\right )} \sqrt {b x^{3} + a}}{b^{2} x^{14} + 2 \, a b x^{11} + a^{2} x^{8}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {B x^{3} + A}{{\left (b x^{3} + a\right )}^{\frac {3}{2}} x^{8}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.10, size = 1018, normalized size = 1.67 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {B x^{3} + A}{{\left (b x^{3} + a\right )}^{\frac {3}{2}} x^{8}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {B\,x^3+A}{x^8\,{\left (b\,x^3+a\right )}^{3/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 136.39, size = 94, normalized size = 0.15 \[ \frac {A \Gamma \left (- \frac {7}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {7}{3}, \frac {3}{2} \\ - \frac {4}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 a^{\frac {3}{2}} x^{7} \Gamma \left (- \frac {4}{3}\right )} + \frac {B \Gamma \left (- \frac {4}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {4}{3}, \frac {3}{2} \\ - \frac {1}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 a^{\frac {3}{2}} x^{4} \Gamma \left (- \frac {1}{3}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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